(4*x+1)*(3-2*x)*(x^2-5)=0

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Solution for (4*x+1)*(3-2*x)*(x^2-5)=0 equation: 



(4x+1)(3-2x)(x^2-5)=0

We add all the numbers together, and all the variables

(4x+1)(-2x+3)(x^2-5)=0

We multiply parentheses ..

(-8x^2+12x-2x+3)(x^2-5)=0

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